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2x^2-3.4x-1.64=0
a = 2; b = -3.4; c = -1.64;
Δ = b2-4ac
Δ = -3.42-4·2·(-1.64)
Δ = 24.68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.4)-\sqrt{24.68}}{2*2}=\frac{3.4-\sqrt{24.68}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.4)+\sqrt{24.68}}{2*2}=\frac{3.4+\sqrt{24.68}}{4} $
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